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ArmAriffic

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Number conversions...

Answer if in Senary 11130151121010101315

Binary

10100111011100110110000111101110010111101100101111

Ternary

10120120120111201120201122010102

Quaternary

2213130312013232113230233

Quinary

1233012043414213421204

Senary

11130151121010101315

Septenary

311060122552533653

Octal

24734660756275457

Nonary

3516514646648112

Decimal

736456024357679

Undecimal

1A372627842106A

Duodecimal

6A72214057A83B

Base 13

257C1674946422

Hexadecimal

29DCD87B97B2F

Vigesimal

3BI7G57C4E3J

Arabic numerals

736456024357679

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Number conversions...

Answer if in Senary 11130151121010101315

Binary

10100111011100110110000111101110010111101100101111

Ternary

10120120120111201120201122010102

Quaternary

2213130312013232113230233

Quinary

1233012043414213421204

Senary

11130151121010101315

Septenary

311060122552533653

Octal

24734660756275457

Nonary

3516514646648112

Decimal

736456024357679

Undecimal

1A372627842106A

Duodecimal

6A72214057A83B

Base 13

257C1674946422

Hexadecimal

29DCD87B97B2F

Vigesimal

3BI7G57C4E3J

Arabic numerals

736456024357679

If that is correct then the binary code converter comes up with "10100111011100110110000111101110010111101100101111: Error: Malformed binary. Your binary code is must be divisible by 8".

Thus either the questions asked are not correctly answered or we have to look at possibilities of translating whatever is hidden in this code in another way - such as hex, for example.

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What about using the answer in binary as morse code?

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What about using the answer in binary as morse code?

you can't do this without knowing pause sequence (morse code needs 3 different chars, not 2)

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If that is correct then the binary code converter comes up with "10100111011100110110000111101110010111101100101111: Error: Malformed binary. Your binary code is must be divisible by 8".

that is a real/correct binary number...I can not comment on the answers...

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In order for a binary number to be divisible by eight, the last three digits need to be 000. (Assuming it's big-endian.)

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their 1st game ^^ and also Father Frost

Edited by Old Bear

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In order for a binary number to be divisible by eight, the last three digits need to be 000. (Assuming it's big-endian.)

yep, tree numbers missing

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Error: Malformed binary. Your binary code is must be divisible by 8".

Ahem...

Whatever application was responsible for this message is botched. It's like saying a decimal number has to have a certain amount of digits.

Binary numbers are just numbers with a different base than 10. Just because computers usually use 8 bits as their smallest storage unit does not make other binary numbers invalid.

---------- Post added at 10:40 AM ---------- Previous post was at 10:40 AM ----------

yep, tree numbers missing

No, just add three leading zeroes to satisfy broken applications

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Ah, so it means the length of the binary number needs to be divisible by eight. Not the number itself.

In that case my 000 suggestion is wrong.

Btw, padding the binary number with zeros only produces gibberish.

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Adding three zeroes to the end of that binary code does not satisfy the broken application.

Tried using another converter and got nothing but nonsense, but for the sake of the cluefinding, this is the nonsense I found:

§saî^Ë

without adding three zeroes. When I DID add the three zeroes, it gave me the same result.

We have to consider firstly if all answers are correct - we have not done so just yet, have we?

Edited by sothis

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Anyway it can be made into a longitude and latitude coordinates?

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Adding three zeroes to the end of that binary code does not satisfy the broken application.

Not to the end... leading zeroes, i.e. at the beginning.

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Adding three zeroes to the end of that binary code does not satisfy the broken application.

Tried using another converter and got nothing but nonsense, but for the sake of the cluefinding, this is the nonsense I found:

You would need to add six zeros to the left. But like I said, it only produces gibberish.

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Adding three zeroes to the end of that binary code does not satisfy the broken application.

Not at the end, at the beginning. You don't usually write "002011" but "2011" because you don't write leading zeros.

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if i take binaries to dived by 7 bits we have 7 values:

164 115 97 238 94 195 192

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Number conversions...

Answer if in Senary 1113 0151 1210 1010 1315

Uhm... the number is supposed to be

1113 0151 1200 1010 1310

right? the 1 in the third block after the 2 is wrong. That was question:

Did all members of Force Recon team Razor survive Operation Harvest Red?

Which is "no" but was assumed "yes" in the beginning by someone.

Edited by Mainstriker

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1113 0151 1200 1010 1310

^^ That's what I got.

Unable to make sense of it so far. This is a tough one.

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1113 0151 1200 1010 1310

^^ That's what I got.

Unable to make sense of it so far. This is a tough one.

same with me, I can confirm

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1113 0151 1200 1010 1310

^^ That's what I got.

Unable to make sense of it so far. This is a tough one.

Important years of some country?

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