Issue returning in functions

[eagledude4 3]

I'd like for someone to explain to me why:

getItemArray = {
_return = [];
if (typeName _this == "STRING") then {
	for "_c" from 0 to ((count INV_AllMissionObjects) - 1) do {
		if (((INV_AllMissionObjects select _c) select 0) == _this) then {
			_return = INV_AllMissionObjects select _c;
		};
	};
} else {
	diag_log format ["ERROR: Input type for %1 was %2 and needs to be STRING", _this, typeName _this];
};

_return;
};

works, and:

getItemArray = {
if (typeName _this == "STRING") then {
	for "_c" from 0 to ((count INV_AllMissionObjects) - 1) do {
		if (((INV_AllMissionObjects select _c) select 0) == _this) exitwith {
			INV_AllMissionObjects select _c;
		};
	};
} else {
	diag_log format ["ERROR: Input type for %1 was %2 and needs to be STRING", _this, typeName _this];
};
};

doesn't.

[mariodu62 5]

using call or spawn for this function ?

[eagledude4 3]

Using call

[mariodu62 5]

but you don't store the result anywhere.

Can you write the main script ?

[Larrow 2822]

Remove the semicolon ; after the line you want returned .. eg

myFunc = {
_randomItems = ["a","b","c","d","e","f","g"];
if (typeName _this == typeName "") then {
	for "_c" from 0 to ((count _randomItems)-1) do {
		if ((_randomItems select _c) == _this) exitWith {
			_randomItems select _c
		};
	};
}else{
	hint "didnt work muppet";
};
};


"c" call myFunc

[eagledude4 3]

Wouldnt the ; after "_return" in my first example be wrong then too?

Edited May 16, 2014 by eagledude4

[Larrow 2822]

Wouldnt the ; after "_return" in my first example be wrong then too?

Following the syntax rules you would generally think so yes. See Return Value on this page https://community.bistudio.com/wiki/Function. Presume as its expecting a returned value that the last expression is used.

[eagledude4 3]

Thanks, Larrow. Bookmarked that page

[Tankbuster 1746]

Yes, don't put a semicolon after the return variable.