Multiarray question

[Ivanoff.N 61]

Hi.

I have a question on arrays.

//I get an output as array eg :

_fruitarray =  [["apple",1],["banana",4],["pear",32]]

//I want to convert it to:

["apple","banana","pear"]

//What would be the correct syntaxis for that ?

//I tried:

{_x select 0} foreach _fruitarray

//but it only shows one of the elements, and I need an array to be returned.

Thanx

[stanhope 412]

_newArray = [];
_fruitarray =  [["apple",1],["banana",4],["pear",32]];
{
	_newArray pushBack (_x select 0);
} foreach _fruitarray;

I didn't test and i literally just woke up so no guarantees :).

_newArray should contain apple, banana, ...

[Ivanoff.N 61]

3 hours ago, stanhope said:

_newArray = [];
_fruitarray =  [["apple",1],["banana",4],["pear",32]];
{
	_newArray pushBack (_x select 0);
} foreach _fruitarray;

I didn't test and i literally just woke up so no guarantees :).

_newArray should contain apple, banana, ...

If I copypaste your code into the console, the output is 2. Don`t quite understand how that happens. (Select 0 gives 2, select 1 gives 2, select 2 gives empty, select 3 and up - zero divisior)

[stanhope 412]

What output are you talking about?  

[Dedmen 2716]

On 15.4.2018 at 1:24 PM, stanhope said:

What output are you talking about?  

He means that it returns 2. Which is the return value of the forEach which is the return value of the last pushBack.
Why are you doing that so complicated?

_fruitarray apply {_x select 0}

Done.

[stanhope 412]

26 minutes ago, Dedmen said:

He means that it returns 2. Which is the return value of the forEach which is the return value of the last pushBack.

I figured as much yes, but wanted to be sure.

 

27 minutes ago, Dedmen said:

Why are you doing that so complicated?

_fruitarray apply {_x select 0}

Done.

Because I didn't know about that command :)

[Ivanoff.N 61]

On 4/16/2018 at 12:37 PM, Dedmen said:

He means that it returns 2. Which is the return value of the forEach which is the return value of the last pushBack.
Why are you doing that so complicated?

_fruitarray apply {_x select 0}

Done.

Yup, that does the job !