alexrandom

This topic working?

So you want say that I have to add 20% to the calculation speed? And it will be the right decision? Or it is necessary take into account also height on which measured wind speeds and repelled from it? One more question: If I shoot from the edge of the ravine, abrupt breakage where there is wind, and on the way to the goal there is no wind. The bullet will use the wind which was at the beginning of the shot or will be are counted each meter (one hundred meters) way?

I do do not speak nothing for speed. I can customize it. Issue of the removal the bullet from the wind. In windless strike targets at me turns. And with the wind (constant, no interference areas) bullet withdraws aside is much stronger than "should". Settings at least no coincide into several tens.

-4 = 100 5 = 1000? I had to take the right by 0.1 Mil to hit the target.

GM6 - does not work SVD - works M14 EBR-RI - works All tests VA, with no wind, and the target angle.

I do not quite understand what you mean. What is green Mil?

Please. Do not write in Fahrenheit. It is unusual for me. I use meters and Celsius. I and so are the settings. Is that the humidity adjusted. But this is not the most important factor. Right? Let me try again to drive your readings speed and posted a video. Let's see what happens. Here, as promised.

Unfortunately, you probably saw that I zeroing temperature differences. Although I get a vertical well. 927m/s=27C 899m/s=4C In the video, with a hit for 2 kilometers were just such settings. Strelok Pro counted based on the introduced amendments to the current velocity. You can also and ballistic coefficient do. But he decided not to touch. Moreover, I zeroed weapon on the map Stratis. In VR, I went for a test with no wind and the angle of the target.

Excuse Me. Do not speak English. Google translator translates. 1. Bullet drop does not match your solver? Bullet drop in temperature does not coincide with the tabulated. My computer has issued droop rate of temperature 1.1 by zeroing. 2 km, as you can see, I hit the target. 2. Windage error? Yes I Am. As noted Ruthberg, error is possible. 3. No Spin drift & Coriolis? When there is no wind and it works. I can not fully answer yet. 4. have you used the correct Ballistics Coefficient? Taken from the table. 5. have you input the correct Ammo & Gun parameters? Taken from the table. 6. have you taken "Muzzle Velocity variation due to powder temp" into account? Detail. Where to look. 7. have you measured the atmospheric condition right (air pressure, temp, humidity)? Every time I conduct measurement at Kestrel. 8. have you considered strong wind which can affect the trajectory? Yes I Am. My computer is calculates. Even more. I calculate degrees from which the wind is blowing and what degrees he blows on the objective. ---------- Post added at 12:07 ---------- Previous post was at 11:42 ---------- Mr. Ruthberg. In your fashion using drag function? Indeed, in the LRR Must be used bullets drag function G-7. Or am I mistaken?

I understand. I have a ballistic computer it takes into account all. I will later throw off screenshots with the translation. ---------- Post added at 22:44 ---------- Previous post was at 21:36 ---------- Here screenshots. Just for you to understand why I'm asking. On me the tests can be put. ))))

Please. So I set up vertically. You have to think what to do with the horizon ...

Added Coriolis effect - on the horizon is a better place to hit the target. But the vertical steel bullets to go a little higher. Judging by Google maps, shooting position on the map Stratis be in latitude 39.52. If I understand where to get the data. ))) And increments marked slot trunk all remain unchanged, even with the Coriolis. I am interested in diverting bullet vertically due to crosswinds. It works? If yes then where you can see the value?

I watched these tables. I use my computer. On Android. Accurate enough. StrelokPro name. This table is written: Rifling Twist 13 in, when I enter 13 in. - The bullets go right. Driven to 6 in - hit the target.

Pardon my Google-Translator. Your mod has a problem with the devaluation. Or cutting tools. Using .408 I need to twist rifling step right up to 6 inches. And it is necessary to have a table with 13 inches. What is the reason? Arma 3. CheyTac M320 LRR .408 (10.36x54mm) "Data on the projectile" Length bullet: 2.126 Bullet diameter: 0.408 Bullet weight, Grain: 416.0 Ballistic coefficient: 0.97 Drag function: G1 Velocity, m / s: 880, 894, 910, 918, 940, 963. Temperature, ÌŠC: -18, 4, 21, 26, 38, 54. Factor sensitivity to temperature: 2.0 "The atmosphere zeroing" Temperature: 21.1 Pressure hPa: 1013 Humidity: 58% "Offset zeroing" (click) Vertical: 0.0 Horizontal: -0.1 "Data on the gun" Zeroing distance: 500 m The height of the sight: 5.0 cm Vertical click MOA (Mil): 1.0 Horizontal click MOA (Mil): 1.0 Net sight: MilDot (USMS) Minimum multiplicity: x10 Multiplicity calibration grid: x84 The maximum multiplicity: x84 Right step rifling of the barrel: 6.0 (need 13) ___________ example: Distance: 1431 m Elevation angle: -4.0 Wind speed: 2.5 m / s Wind direction: 255 Direction to the target: 005 Temperature ÌŠC: 24.4 Pressure hPa: 982 Humidity: 57% __________ The result at the right step marked slot trunk = 6.0 and windage -0.1: Vertical: MOA = 30.22, MRAD = 8.79, cm = 1257.8, click = 8.8 Horizontal: MOA = -3.44, MRAD = -1.0, cm = 143.1, click = -1.0 Hit 3-5 / 5 __________ The result at the right step marked slot barrel = 13 without amendment: Vertical: MOA = 30.22, MRAD = 8.79, cm = 1257.8, click = 8.8 Horizontal: MOA = -2.34, MRAD = -0.68, cm = 97.4, click = -0.7 Slip the right. That's what brings me to your computer.