Operating with Arrays

[logan83 11]

Hi Guys! I'm stuck on one of those things that look easy, but then they are not. Im going to explain my self... I Have two arrays

_ArrayA = [1,2,3];
_ArrayB = [2,1,0];

If I try to add them together, I get:

_ArrayC = _ArrayA + _ArrayB;
hint str _arrayc;

_ArrayC returned  [1,2,3,2,1,0], oks my question Now... How can i add each value to get [3,3,3] not [1,2,3,2,1,0]. Im sorry but my english not good enought. :(

[BlacKnightBK 47]

5 minutes ago, logan83 said:

Hi Guys! I'm stuck on one of those things that look easy, but then they are not. Im going to explain my self... I Have two arrays

_ArrayA = [1,2,3];
_ArrayB = [2,1,0];

If I try to add them together, I get:

_ArrayC = _ArrayA + _ArrayB;
hint str _arrayc;

_ArrayC returned  [1,2,3,2,1,0], oks my question Now... How can i add each value to get [3,3,3] not [1,2,3,2,1,0]. Im sorry but my english not good enought. :(

 

a loop

_ArrayC = [];
for "_i" from 0 to ((count _ArrayA)-1) do {

	_value = (_arrayA select _i) + (_ArrayB select _i);

	_arrayC pushback _value;
};

hint _arrayC;

 

 

[sarogahtyp 1108]

if the arrays are 3D vectors as in ur example then you should do it with vectorAdd:

_arr1 = [1,2,3]; 
_arr2 = [3,2,1]; 
_arr3 = _arr1 vectorAdd _arr2;

hint format["%1", _arr3]; //throws [4,4,4]

if your arrays are not such vectors then I woul do a loop as well but i would choose forEach

_arr1 = [1,2,3,4];  
_arr2 = [3,2,1,0]; 
_arr3 = []; 
 
{
 _value = _x + (_arr2 select _forEachIndex);
 _arr3 pushBack _value;
} forEach _arr1; 

hint format["%1", _arr3]; //throws [4,4,4,4]

EDIT:

here is another solution which is not creating a third array. it just modifies _arr2. this should be faster but the contents of _arr2 are changed after that:

_arr1 = [1,2,3,4];  
_arr2 = [3,2,1,0]; 
 
{
 _value = _x + (_arr2 select _forEachIndex);
 _arr2 set [_forEachIndex, _value];
} forEach _arr1; 

hint format["%1", _arr2]; //throws [4,4,4,4]

 

Edited April 12, 2017 by sarogahtyp
Inserted another method

[BlacKnightBK 47]

44 minutes ago, sarogahtyp said:

if the arrays are 3D vectors as in ur example then you should do it with vectorAdd:

_arr1 = [1,2,3]; 
_arr2 = [3,2,1]; 
_arr3 = _arr1 vectorAdd _arr2;

hint format["%1", _arr3]; //throws [4,4,4]

if your arrays are not such vectors then I woul do a loop as well but i would choose forEach

_arr1 = [1,2,3,4];  
_arr2 = [3,2,1,0]; 
_arr3 = []; 
 
{
 _value = _x + (_arr2 select _forEachIndex);
 _arr3 pushBack _value;
} forEach _arr1; 

hint format["%1", _arr3]; //throws [4,4,4,4]

 

 

Yeah for each is better than a for loop, reason i did it for loop is that's how i did it in java and c++

[logan83 11]

Great! Thanks to you both guys!! You'res my heroes! 

 

[logan83 11]

uhm, another question, how can i make this cleaner?

_unitpos = this select 0;
_DropPos = [];
if (_UnitPos == 1) then {_DropPos pushBack .8; _DropPos pushBack 3.18; _DropPos pushBack 1.16594};

Cause if i use:

if (_UnitPos == 1) then {_HaloPos pushBack [.8,3.18,1.16594]};

_HaloPos returns [[0.8,3.18,1.16594]] instead of [0.8,3.18,1.16594]...

 

Sorry about the stupid questions but im newbie :(

[sarogahtyp 1108]

I dont get the point.

What should that script do?
If you only want to get those values in an array then just use:

_HaloPos = [.8,3.18,1.16594];

 

[BlacKnightBK 47]

7 minutes ago, logan83 said:

uhm, another question, how can i make this cleaner?

_unitpos = this select 0;
_DropPos = [];
if (_UnitPos == 1) then {_DropPos pushBack .8; _DropPos pushBack 3.18; _DropPos pushBack 1.16594};

Cause if i use:

if (_UnitPos == 1) then {_HaloPos pushBack [.8,3.18,1.16594]};

_HaloPos returns [[0.8,3.18,1.16594]] instead of [0.8,3.18,1.16594]...

 

Sorry about the stupid questions but im newbie :(

 

As Saro said, you can just put them in in the array straight

_unitpos = this select 0;
_DropPos = [];
if (_UnitPos == 1) then {_DropPos = [0.8,3.18,1.16594]};

 

[logan83 11]

ok i trying to set objets positions relative to a another Object position, i cant use attachto or something, and the base object has a random start. Sorry about my english i cant explain myself better :( 

[sarogahtyp 1108]

_offset = [0, 0, 10];
_obj1 setPos (_obj2 modelToWorld _offset);

_ obj1 is the object which should be attached to _obj2

_offset is the offset which should be used

[logan83 11]

20 minutes ago, sarogahtyp said:

_offset = [0, 0, 10];
_obj1 setPos (_obj2 modelToWorld _offset);

_ obj1 is the object which should be attached to _obj2

_offset is the offset which should be used

I feel very stupid right now... better take a break, my head its burning xDD thanks a lot sarogahtyp.

[BlacKnightBK 47]

2 minutes ago, logan83 said:

I feel very stupid right now... better take a break, my head its burning xDD thanks a lot sarogahtyp.

bro i feel like that every time he corrects me, but don't worry bro :) it just means we are learning

[sarogahtyp 1108]

its just about reading the wiki and I m far far away from understanding all the stuff in armas scripting.

The important thing is to read the examples and the comments in the wiki. And also try, try, try...

[logan83 11]

// null = [player,1,Tresure,RescuePlane] execVm "scripts\location.sqf";

_unit =	_this select 0;
_UnitPos = _this select 1;
_load = _this select 2;
_Plane = _this select 3;

if (_UnitPos == 1) then {_OffsetPos = [1,3.18,1.16594]};
if (_UnitPos == 2) then {_OffsetPos = [.8,4.97,1.16594]};

_unit setpos (_Plane modelToWorld _OffsetPos);

my mind blowup, this returnme _OffsetPos not defined... im let this for today :(

[sarogahtyp 1108]

_OffsetPos is a local variable and as this it is only known in its scope. In ur script the scope is the if statement,
just initialize it at the beginning of ur script like this:

_OffsetPos = [];

to clarify that:

if you set a local variable within a pair of {} brackets only then that variable is not known outside of those brackets

[logan83 11]

1 hour ago, sarogahtyp said:

_OffsetPos is a local variable and as this it is only known in its scope. In ur script the scope is the if statement,
just initialize it at the beginning of ur script like this:

_OffsetPos = [];

to clarify that:

if you set a local variable within a pair of {} brackets only then that variable is not known outside of those brackets

yea i forget... too many hours... im having a breack now watching VIKINGs xD need to refresh my mind, thank u  saro.