Will be posting some csat questions for practice here on a daily basis!

50. There are 2 candidates P & Q in an election. During the campaign, 40% of the voters promised to vote for P and rest for Q. However, on the day of election 15% of the voters went back on their promise to vote for P and instead voted for Q. 25% of the voters went back on their promise to vote for Q and instead voted for P. Suppose P lost by 2 votes, then what was the total number of voters?

48.

Let number of boys who participated= 4x

Let number of girls who participated =3x

no of candidates who passed the examination= 80% of 7x= (28x/5)no of girls who passed the examination= 90% of 3x= (27x/10)So, no of boys who passed the examination= (28x/5)- (27x/10)= (29x/10)As %= (29/40)*100= 72.5%

Correct

48. The ratio of number of boys and girls who participated in an examination is 4:3. The total percentage of candidates who passed the examination is 80, and the percentage of girls who passed the exam is 90. The percentage of boys who passed the exam is?

boy = 4x ; girl = 3x ; total = 7x

total passed is 80% =>0.8 * 7x = 5.6x

girls passed is 90% =>0.9* 3x = 2.7x

hence boy passed = 5.6x-2.7x = 2.9x

pass percentage = 2.9x / 4x =0.725 or 72.5 %

50. There are 2 candidates P & Q in an election. During the campaign, 40% of the voters promised to vote for P and rest for Q. However, on the day of election 15% of the voters went back on their promise to vote for P and instead voted for Q. 25% of the voters went back on their promise to vote for Q and instead voted for P. Suppose P lost by 2 votes, then what was the total number of voters?

total voter = 100x

p q

1st eqn 40x 60x

2nd eqn -6x +6x

3rd eqn +15x -15x

total = 49x 51x

As the final difference between them = 2 (given) = 51x - 49x;

hence x=1;

total voter = 100.

50. There are 2 candidates P & Q in an election. During the campaign, 40% of the voters promised to vote for P and rest for Q. However, on the day of election 15% of the voters went back on their promise to vote for P and instead voted for Q. 25% of the voters went back on their promise to vote for Q and instead voted for P. Suppose P lost by 2 votes, then what was the total number of voters?

total voter = 100x

p q

1st eqn 40x 60x

2nd eqn -6x +6x

3rd eqn +15x -15x

total = 49x 51x

As the final difference between them = 2 (given) = 51x - 49x;

hence x=1;

total voter = 100.

Correct

**@Neyawn**option A

**@Neyawn**ideally answer should be cannot be determined....it should have clarified that their ages 3 years prior were natural number...otherwise 114